Plotting a circular vector field

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SUMMARY

The discussion centers on sketching the vector field defined by the equation G(x,y) = \frac{-iy + jx}{\sqrt{x^2+y^2}}. Participants confirm that all vectors derived from this equation maintain a constant magnitude of 1, regardless of the input values for x and y. A key suggestion is to evaluate the magnitude of an arbitrary vector in terms of x and y to verify this property. The conversation emphasizes that plotting the vector field will only require consideration of the direction since the magnitude remains constant.

PREREQUISITES
  • Understanding of vector fields and their properties
  • Familiarity with LaTeX for mathematical expressions
  • Knowledge of magnitude calculation for vectors
  • Basic concepts of polar coordinates and their relation to Cartesian coordinates
NEXT STEPS
  • Explore the derivation of vector magnitudes in polar coordinates
  • Learn about visualizing vector fields using tools like MATLAB or Python's Matplotlib
  • Investigate the implications of vector field directionality in physics
  • Study the behavior of vector fields at singular points, such as the origin
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Students in mathematics or physics, particularly those studying vector calculus, as well as educators looking to enhance their understanding of vector fields and their graphical representations.

bitrex
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Homework Statement


I'm supposed to sketch the vector field and verify that all the vectors of the following equation have the same length.

Homework Equations



[tex]G(x,y) = \frac{-iy + jx}{\sqrt{x^2+y^2}}[/tex]

The Attempt at a Solution



If I start plugging in numbers, for example the point (1,1) into [tex]\frac{-iy}{\sqrt{x^2+y^2}}[/tex] and into [tex]\frac{jy}{\sqrt{x^2+y^2}}[/tex] I move minus 1 unit along the x axis, and up one unit along the Y axis. So that vector has a length of 1 unit. But if I put in (2,2) to the same equation I move [tex]\frac{-2}{\sqrt{8}}[/tex] in the negative X direction and the same in the positive Y direction. I don't see ho..Oh. Now that I'm typing it out in LaTeX I see it. If I take the magnitude of the new i,j vector I get from evaluating the equation, I'm going to get 1 aren't I? And no matter what values I plug into the original equation, the magnitude of the resulting vector is always going to work out to 1. Does that sound correct?
 
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hey bitrex, sounds like you're heading in the right direction

try taking the magintude of an arbitrary vector (in terms of x,y) and see if it simplifies to one, then you've shown it for every x,y, though you may have to be careful at the origin.

Then plotting will only involve the direction of the vector as the magnitude is constant.
 
What is
[tex]\sqrt{\left(\frac{-y}{\sqrt{x^2+ y^2}}\right)^2+ \left(\frac{x}{\sqrt{x^2+ y^2}}\right)^2[/tex]
It's that easy.
 

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