Point discontinuity problem

  • Thread starter neuro.akn
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  • #1
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Homework Statement



Find the value of p at which the discontinuity would occur.


Homework Equations



f(x) = x^2 - 6x + 9 / x - p

The Attempt at a Solution



Able to solve if p has an assigned numerical value, but help is needed for determining the value of p at which the discontinuity would occur. Any help is appreciated. Thank you.
 

Answers and Replies

  • #2
pasmith
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Factorize [itex]x^2 - 6x + 9[/itex].
 
  • #3
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Okay. Thanks; once I have done that, how would I solve for p?
 
  • #4
pasmith
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If you haven't yet found the answer to your other problem, I would suggest you do that and then come back to this problem, at which point the solution will hopefully be obvious.

In any event I would recommend re-reading the material on which these problems are based, since you don't seem to be fully comfortable with it.
 
  • #5
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A discontinuity occurs when you cannot determine the function value at a certain argument(x) value. There's an operation only Chuck Norris can do..or so they say.

X-p , you know that there is one value that it can't have since it's in the denominator.
You also know that the function at 1st glance Could be 0 when X=?? according to the numerator.

What's the 1 value that cannot be P? Everything else can. Think of a hyperbole.
 
Last edited:
  • #6
Ray Vickson
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Homework Statement



Find the value of p at which the discontinuity would occur.


Homework Equations



f(x) = x^2 - 6x + 9 / x - p

The Attempt at a Solution



Able to solve if p has an assigned numerical value, but help is needed for determining the value of p at which the discontinuity would occur. Any help is appreciated. Thank you.
As in your other posting: you need parentheses! If I read what you wrote using standard rules for mathematical expressions, I would see
[tex] f(x) = x^2 - 6x + \frac{9}{x} - p.[/tex]
 
Last edited:
  • #7
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Ray Vickson, (x^2 - 6x + 9) / (x - p)
Thank you all for your help.
 
  • #8
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The thing is, we have not gone over this material at all.
 
  • #9
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I have solved the problem. Thank you everyone.
 

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