Pointwise convergence of integral of Fourier series

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SUMMARY

The discussion centers on proving that the indefinite integral F(x) = ∫-Lx f(s) ds of a piecewise-continuous function f(x) in the interval [-L, L] has a full Fourier series that converges pointwise. The full Fourier series is expressed as f(x) = (1/2)A0 + Σn=1 (An cos(nπ/L x) + Bn sin(nπ/L x)). The key to the solution involves justifying the term-by-term integration, which requires establishing uniform convergence.

PREREQUISITES
  • Understanding of Fourier series and their coefficients (An, Bn)
  • Knowledge of piecewise-continuous functions
  • Familiarity with the concept of pointwise convergence
  • Basic principles of uniform convergence in analysis
NEXT STEPS
  • Study the conditions for uniform convergence of Fourier series
  • Learn about the properties of piecewise-continuous functions
  • Explore the implications of term-by-term integration in series
  • Investigate the relationship between Fourier series and integral convergence
USEFUL FOR

Mathematics students, particularly those studying real analysis and Fourier analysis, as well as educators seeking to deepen their understanding of convergence in the context of Fourier series.

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Homework Statement


If f(x) is a piecewise-continuous function in [-L,L], show that its indefinite integral F(x) = \int_{-L}^x f(s) ds has a full Fourier series that converges pointwise.

Homework Equations


Full Fourier series: f(x)=\frac{1}{2}A_0 + \sum_{n=1}^\infty A_n \cos (\frac{n \pi }{L}x) + B_n \sin (\frac{n \pi}{L}x)

Definition: \sum_{n=1}^\infty f_n (x) converges to f(x) pointwise in (a,b) if for each a<x<b we have
\Big| f(x) - \displaystyle{\sum_{n=1}^\infty f_n (x)} \Big| \to 0 as N\to\infty.

The Attempt at a Solution


I think I need to somehow justify integrating term-by-term, but am not sure how to proceed. Any ideas?
 
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If you want to integrate term by term, you need uniform convergence.
Haven't really looked at this, so not saying that term by term integration is the solution here.
 

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