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buddingscientist
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Hello In my text the following question is posed:
ON a city street, car backfires are heard 8 times per hour. Use the poisson distribution to find an exact expression for the prob. that a car backfire is heard at most once in a given hour. Do not simplify or evaluate your answer.
Now from my understanding, in the poisson distribution, mean = variance = 'parameter'
In the question we can assume that the mean equals 8, thus letting the parameter = 8.
A car backfire is heard at most once in a given hour.
= Probability of hearing 0 backfires + probability of hearing 1 backfire
= 8^0 e^(-8) / 0! + 8^1 e^(-8) / 1!
= e^(-8) + 8e^(-8)
= 9e^(-8)
Is this the correct solution? Thanks for your time
ON a city street, car backfires are heard 8 times per hour. Use the poisson distribution to find an exact expression for the prob. that a car backfire is heard at most once in a given hour. Do not simplify or evaluate your answer.
Now from my understanding, in the poisson distribution, mean = variance = 'parameter'
In the question we can assume that the mean equals 8, thus letting the parameter = 8.
A car backfire is heard at most once in a given hour.
= Probability of hearing 0 backfires + probability of hearing 1 backfire
= 8^0 e^(-8) / 0! + 8^1 e^(-8) / 1!
= e^(-8) + 8e^(-8)
= 9e^(-8)
Is this the correct solution? Thanks for your time
