I am trying to find the polar notation for(adsbygoogle = window.adsbygoogle || []).push({});

1 + e^(j4)

I know that e^(jx) = cos x + jsin x

= cos(4) + jsin(4)

I can then find the magnitude and angle.

This is nowhere close to the answers below.

1) cos(2) + 1

2) e^(j2)[2cos(2)]

3) e^(-j4)sin(2)

4) e^(j2)(1+2cos(2))

Can anyone point me in the right direction?

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# Homework Help: Polar notation for a complex exponential function

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