Positive and negative square roots

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SUMMARY

The discussion focuses on determining positive and negative square roots in equations, emphasizing the necessity of verification after solving. It highlights that while both positive square roots may yield valid solutions, negative square roots often do not apply, particularly in real numbers. The participants agree that squaring both sides of an equation is essential for finding roots but may not guarantee equivalence unless all solutions are verified by substitution back into the original equation.

PREREQUISITES
  • Understanding of square roots and their properties
  • Familiarity with algebraic equations and manipulation
  • Knowledge of verification methods in solving equations
  • Basic concepts of real and complex numbers
NEXT STEPS
  • Study the properties of square roots in algebra
  • Learn about verification techniques for algebraic solutions
  • Explore the implications of squaring both sides of an equation
  • Investigate the differences between real and complex roots
USEFUL FOR

Students, educators, and anyone involved in algebra who seeks to deepen their understanding of square roots and the importance of solution verification in mathematical equations.

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how to determine which is the answer to positive sqrt and negative sqrt in this problem?

substituting works but what if the equation is very long and you can't use calcu or computers

http://i.imgur.com/SkcQZ.png

also is there a way to solve this without squaring both sides?
 
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actually both are positive sqrt answers because there is no negative sqrt answer

also i think negative sqrt answers will come naturally.

but still, is there a way to solve this without squaring both sides?
 
This is why one has to do verification after solving an equation (unless he can guarantee that every step of the solution process is an equivalence ). In the case we consider only the negative or only the positive sqrt, when we square both sides we don't produce an equivalence. In the case we take both then we have an equivalence but there is no way to know which root belongs to which case unless we substitute the solutions to the original equation.

In this example the equation +sqrt(...)=1-x has two roots in R but the equation -sqrt(...)=1-x has no root in R (and no root in C also). I don't see other way to show the latter result, other than squaring, finding the two roots and then by substitution in the original equation to find out that they don't verify it.
 

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