Possible combinations with thirteen buttons

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The discussion revolves around determining the number of possible combinations for a lock with 13 buttons, each of which can be either pressed in or left out. The exact number of buttons that need to be pressed is unknown, leading to various potential combinations. A mathematical approach suggested involves labeling each button's position as either 0 (not pressed) or 1 (pressed) and using the binomial expansion of (1+1)^13 to calculate the combinations. This method allows for the identification of the number of ways to press any k buttons from the total of 13. Ultimately, the conversation highlights the complexity of the lock's mechanism and the mathematical principles that can be applied to solve the problem.
davidbdix
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This is similar to one of my previous posts, but is quite different.
There are 13 buttons (numbered 1, 2, 3, ...13)in this combination lock, and you have to figure out which ones can be pressed in.
They can either be pushed in or left into their original extended position.
You don't know how many buttons need to be pushed in (or left pushed out) to solve the lock (it could be none, 1, 3, 8, or all 13).
How many possibile combinations are there? Any how do you arrive at that answer?

Here's a photo of my lock. The buttons are in the front of the blanket chest and are spring-loaded. When you push one of the buttons, the corresponding lock-pin on the top of the chest falls into place due to gravity. To let the lock return to the original position, you pull the lock-pin upwards and the spring forces the button back out. After each attempt at pushing the buttons, the longer bar on top of the chest gets pushed down. If the combination is correct, you can push the bar all the way down. If incorrect, it only depressed part of the way.
 

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hi davidbdix! :smile:

have you tried labelling each button's position as either 0 or 1 ?
 
(I answered on another forum). 213. Expand (1+1)13 as binomial. The kth term is the number of ways to press k buttons.
 
thanks!
 
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