Possible Triplets for (1+1/a)(1+1/b)(1+1/c)=3

  • Thread starter rattanjot
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In summary, the equation (1+1/a)(1+1/b)(1+1/c)=3 can have infinite possible solutions with any positive real numbers for a, b, and c. It can be solved using algebraic techniques and there are no restrictions on the values of a, b, and c.
  • #1
rattanjot
4
0
let a,b,c be integers
how many triplets are possible for
(1+1/a)(1+1/b)(1+1/c) = 3
 
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  • #2
Why don't you multiply it out and see what happens?
 
  • #3
Consider that a≥b≥c. can u please tell the maximum value of c..!
 
  • #4
What have you tried so far? Yours seems like a standard max/min problem that can be done, e.g., by Lagrange multipliers.
 
  • #5
What are Langrange multipliers..??
 
  • #6
Maybe if you tell us more about the context of the problem and the areas that you

know, we can have a better way of suggesting something useful.
 

1. What is the equation for "Possible Triplets for (1+1/a)(1+1/b)(1+1/c)=3"?

The equation is (1+1/a)(1+1/b)(1+1/c)=3.

2. What are the possible values for a, b, and c in the equation?

The possible values for a, b, and c are any positive real numbers.

3. How can this equation be solved for the possible triplets?

This equation can be solved by using algebraic techniques such as factoring, substitution, or expanding the terms.

4. Are there any restrictions on the values of a, b, and c?

There are no restrictions on the values of a, b, and c as long as they are positive real numbers.

5. Can this equation have more than one solution?

Yes, this equation can have infinite possible solutions, as there are infinite possible combinations of positive real numbers for a, b, and c that can satisfy the equation.

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