Potential energy of a loaded structure

AI Thread Summary
In a loaded structure, the potential energy of the system is minimized in its equilibrium state, as illustrated by the gravitational interaction between a person and the Earth. When standing still, the potential gravitational bond energy is zero, representing a stable equilibrium. If the person moves away from this state, the potential energy increases, demonstrating that energy is gained when moving away from equilibrium. Upon returning to the equilibrium position, kinetic energy is gained while potential energy decreases back to zero. This illustrates that potential energy is minimized at the equilibrium state of the loaded structure.
chandran
Messages
137
Reaction score
1
can anyone proove the following

"IN A LOADED STRUCTURE THE POTENTIAL ENERGY OF THE SYSTEM IS MINIMUM IN ITS EQUILIBRIUM STATE"
 
Physics news on Phys.org
Unless you are willing to put some CONTEXT where such a statement is applied, then such a thing is rather meaningless. Don't be surprised if you end up with replied that have nothing to do with what you are thinking of.

Zz.
 
Here is one simplistic non mathematical attempt to answer:

Suppose while I stand on the Earth I am a "loaded structure" gravitationally with the earth, we both attract each other with equal force. The Earth and I are in our ultimate equilbrium and stable state with respect to each other as a "loaded structure", thus our potential gravitational bond energy P = 0. I now transform the system and I walk up one unit of distance away from ultimate equilbrium state with the earth. Potential gravitational bond energy for the system has now increased to P = +1. Next, I step back down one unit of distance. During the process of stepping down I gain kenetic energy and lose potential gravitational bond energy, I return to P =0 state. Thus, the potential bond energy (P) of the loaded system (me & earth) is minimum (=0) at our ultimate stable equilbrium state.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top