Potential Energy to bring in sphere from infinity

AI Thread Summary
The discussion focuses on calculating the work done to bring the mass of a uniform sphere from infinity, leading to the self-potential energy formula P = -3/5 (GM²/R). The user initially derived the work using integral calculus but encountered confusion regarding the application of the force and the role of the unit vector. They clarified that the uniform mass distribution implies a constant mass-to-volume ratio, which is crucial for the calculations. The conversation also addressed the wording of the problem, with participants agreeing that it could be clearer. Ultimately, the user reported successfully solving the problem with help from others in the thread.
Sentin3l
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Homework Statement



Given a uniform sphere of mass M and radius R. Use integral calculus and start with a mass dm in the sphere. Calculate the work done to bring in the remainder of the mass from infinity. By this technique show that the self-potential energy of the mass is:

P = -\frac{3}{5} \frac{GM^{2}}{R}​



Homework Equations



W = \int\vec{F} \bullet d\vec{r}
F = \frac{GMm}{r^{2}}​


The Attempt at a Solution



First let me say that this is a cosmology question. I began by considering a differential mass near or at the center of the sphere. Using the above equations for force and work, I derived:

W = - \int \frac{GM(dm)}{r^{2}} \hat{r}​

Since the sphere is uniform, it has a constant mass to radius ratio λ = \frac{M}{R} = \frac{dm}{dr}. So using this I found:


W = -λ\int \frac{GM}{r^{2}}dr = -3λ \frac{GM}{r^{3}}​

If we substitute λ = \frac {M}{R} and r=R, we get the result:

W = -3 \frac{GM^{2}}{R^{3}}​

Here is where i think I went wrong, I don't know if I need to deal with \hat{r} and if so, I'm not sure how to approach that.

I think that once I get the work, you use the work-energy theorem, and intial/final KE is 0 so the potential energy equals the work, please correct me if I'm wrong in that.
 
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Sentin3l said:
Since the sphere is uniform, it has a constant mass to radius ratio λ = \frac{M}{R} = \frac{dm}{dr}.

Uniform mass distribution means that the mass to volume ratio is constant.
 
The problem is worded kind of strangely. Consider when the mass that's already been brought in occupies a sphere of radius ##r##. How much work is required to bring in the mass to increase the radius by dr?
 
TSny said:
Uniform mass distribution means that the mass to volume ratio is constant.
Should I use my previous integral, taking note that dV = 4 \pi r^{2} dr ?
vela said:
The problem is worded kind of strangely. Consider when the mass that's already been brought in occupies a sphere of radius ##r##. How much work is required to bring in the mass to increase the radius by dr?

I agree that the problem is worded strangely, it's a recurring problem with this textbook. Also I'm not sure what your mean in your suggestion, did you mean "How much work is required to bring in the mass to decrease the radius by dr"?
 
Last edited:
No. Why would you want to decrease the amount of mass there when you're building it up?
 
I have solved the problem, thanks to you both for the assistance.
 
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