Potential of terminals of battery

  • Thread starter Thread starter gracy
  • Start date Start date
  • Tags Tags
    Battery Potential
AI Thread Summary
The discussion centers on the potential of battery terminals, specifically a 9V battery, and the concept of potential difference. It emphasizes that while various potential values can be assigned to the positive and negative terminals, the actual potential is relative to a reference point, which is often unspecified. The potential difference of 9V remains constant regardless of how the terminals are grounded or referenced. The conversation highlights that understanding the relative potential is crucial in certain contexts, although it may not always be necessary for practical applications. Ultimately, the focus is on the significance of potential differences over absolute terminal potentials.
gracy
Messages
2,486
Reaction score
83
No it is not a homework problem I made it myself in order to clearly explain what I am trying to ask.The question could be invalid and silly therefore .If there is a 9V battery What is the potential of it's positive and negative terminals respectively?

If positive terminal's potential is 3V and potential of negative terminal -6V then there would be potential difference of 9V. Similarly if positive terminal's potential is 2V and potential of negative terminal -7v then there would be potential difference of 9V. So many answers are possible therefore potential of one terminal should be given.
Am I making sense?Or all of these are wrong?
 
Physics news on Phys.org
Only potential differences are physically meaningful. Given a battery with a potential difference of 9 V between the two terminals, there is not enough information to tell you the potential of either positive or negative terminal relative to some unspecified reference.

For instance, you could ground the positive terminal. The negative terminal would then be at -9 V relative to the ground. Or you could ground the negative terminal. The positive terminal would then be at +9 V relative to the ground. Or, as you suggest, you could arrange for the two terminals to be at +3 V and -6 V. That would be perfectly reasonable.
 
  • Like
Likes gracy
gracy said:
If positive terminal's potential is 3V and potential of negative terminal -6V then there would be potential difference of 9V. Similarly if positive terminal's potential is 2V and potential of negative terminal -7v then there would be potential difference of 9V. So many answers are possible therefore potential of one terminal should be given.
Am I making sense?Or all of these are wrong?

You are basically correct.

However ask yourself 3V relative to what ?... and do you really need to know the voltage relative to that? My phone works just fine even when my hand is charged to several thousand volts by static electricity. Sometimes it does matter. Can you think of a situation?
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top