# Power Consumption

1. Jul 10, 2009

### NikkiNik

1. The problem statement, all variables and given/known data

(a)A 60 W, 115 V lightbulb has a resistance of 10.9 W when cold (20.0°C) and 132 W when on (hot). Calculate its power consumption at the instant it is turned on.

(b)Calculate its power consumption after a few moments when it is hot

2. Relevant equations

P=V^2/R

3. The attempt at a solution

I tried adding and subtracting the resistances then dividing the voltage squared by either values but that is incorrect. I don't know how to determine how much power is used when the switch is turned on. Since I don't know the first answer I can't solve the second part which I assume I would use the Power found in part a and divide the voltage squared by that number

2. Jul 10, 2009

### cepheid

Staff Emeritus
I think you mean 10.9 Ω and 132 Ω right? You can just write "ohms" if you don't have the symbol for it, but it is very important to get the units right. Resistance is not the same thing as power, and therefore, they are not measured using the same units!

The equation you posted gives you the power dissipated in a resistor having resistance R and voltage V applied across it. Period.

In this situation, you have two different situations, each with a different R, but the same V (because the resistance of the lightbulb changes with temperature, but the voltage being applied across it is being kept steady). Can you calculate the power for each of these two different situations?

3. Jul 10, 2009

### LowlyPion

For V, I think you will want to use the Vrms for figuring power. This is AC current. If it was DC you could use 115 straight.

4. Jul 10, 2009

### cepheid

Staff Emeritus
AC power is always quoted as RMS (e.g. the 230 VAC or 120 VAC) anyway. Furthermore, although we know that the voltage is AC, this is not stated explicitly in the question, suggesting that the OP isn't supposed to worry about it either way.

5. Jul 10, 2009

### NikkiNik

I didn't realize I posted W instead of omega. Yes I know how to calculate individual powers but I don't understand how I could figure out the power consumed the instant it is turned on. How am I supposed to know the resistance? How do I what the temperature is?

6. Jul 10, 2009

### Redbelly98

Staff Emeritus
The lightbulb is "cold" at the instant it is turned on, and "hot" after being on a few moments.

7. Jul 10, 2009

### Phrak

Be sure to properly time your experiment.
One moment = 1.5 minutes.
http://www.unc.edu/~rowlett/units/dictM.html" [Broken]

I'm searching for the meaning of 'few'.
Be back in three shakes.

Last edited by a moderator: May 4, 2017
8. Jul 11, 2009

### NikkiNik

Man I was really overthinking the problem!!! Thank you for your help