Power delivered to each source. Image included

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The discussion revolves around calculating the total power delivered by each source and its comparison to the power delivered to the load RL. The correct answer for the total power is identified as 72 W, but confusion arises regarding the method to derive this figure. Participants express uncertainty about the relationship between the power calculations and the load resistance, with one suggesting that symmetry in the circuit implies equal power distribution between the sources. Additionally, there is a query about the clarity of the homework questions, particularly regarding the phrasing in part C. The conversation highlights the challenges in understanding circuit power dynamics and the implications of source symmetry.
Josh225
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Homework Statement


I got the correct answers for A and B, I just need help with C and D.

A. Find indicated currents. I1= I2 = 3 A ... IL = 6 A

B. Find total power delivered by each source. PE = 12 V (3A)

C. Find the total power delivered by each source and compare it to the power delivered to the load RL.

D. If only source current was available, what would the current drain be to supply the same power to the load? How does the current level compare to the calculated level of part A.

Homework Equations


PE = E Is

Is = E/ RT

The Attempt at a Solution


A. Find indicated currents. I1= I2 = 3 A ... IL = 6 A

B. Find total power delivered by each source. PE = 12 V (3A)

C. It says the answer is 72 W, but I am unsure how to get there. I figured that I would find RL by applying ohms law (R= V/I ... R=12/3 = 4 ohms) then subtracting it from PL (72 W), but that gets me the wrong answer.

D. For D, I am not so sure..
 

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C is a question (find the power) followed by an instruction (to make a comparison). The question part looks identical to question B, other than an apparently unimportant 'the'. Are you sure you have typed in the questions correctly?

Also, if we are told that 72W is being dissipated in the resistance, doesn't the symmetry between the two batteries in the circuit dictate that each must be supplying half of that power, without having to do any calculations?
 

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