soupastupid Messages 34 Reaction score 0 Thread starter Oct 22, 2008 #1 Homework Statement Homework Equations P=F*V The Attempt at a Solution why isn't it P = Cd(A^2)(v^2) * (v) i don't see what i could do Attachments power dissipation.jpg 61.5 KB · Views: 445
Homework Statement Homework Equations P=F*V The Attempt at a Solution why isn't it P = Cd(A^2)(v^2) * (v) i don't see what i could do
Doc Al Mentor Messages 45,587 Reaction score 2,468 Oct 23, 2008 #2 soupastupid said: Homework Equations P=F*V This is correct. The Attempt at a Solution why isn't it P = Cd(A^2)(v^2) * (v) But this is not. You made an error when you substituted for F in the power equation. Redo it, paying attention to each factor in the drag formula.
soupastupid said: Homework Equations P=F*V This is correct. The Attempt at a Solution why isn't it P = Cd(A^2)(v^2) * (v) But this is not. You made an error when you substituted for F in the power equation. Redo it, paying attention to each factor in the drag formula.
soupastupid Messages 34 Reaction score 0 Oct 23, 2008 #3 ok i figured out the first part how do i figure out part B? I kno the power is proportional to v^3 and so if i increase the power by 10% i should get ?? if Pi = -(vi^3)AC_d then 1.1Pi=-(vf^3)AC_d Pi = (-(vf^3)AC_d ) / 1.1 (vf^3) = 1.1(vi^3) then what? Attachments power dissipation.JPG 58.2 KB · Views: 437
ok i figured out the first part how do i figure out part B? I kno the power is proportional to v^3 and so if i increase the power by 10% i should get ?? if Pi = -(vi^3)AC_d then 1.1Pi=-(vf^3)AC_d Pi = (-(vf^3)AC_d ) / 1.1 (vf^3) = 1.1(vi^3) then what?
Doc Al Mentor Messages 45,587 Reaction score 2,468 Oct 23, 2008 #4 Solve for Vf in terms of Vi. (Take the cube root of both sides.)