Power factor of a transformer at 80%

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SUMMARY

The power factor (PF) of a transformer operating at 80.1% of full load remains constant, as demonstrated by the equation PF = P / S, where both output power (P) and apparent power (S) are proportional to the load. The discussion clarifies that the units of apparent power (S) are volt-amperes and raises questions about the nature of the load, specifically whether it is purely resistive. Additionally, the impact of magnetizing current on the power factor at this load level is explored.

PREREQUISITES
  • Understanding of power factor calculations in electrical engineering
  • Familiarity with transformer operation and load characteristics
  • Knowledge of electrical units, specifically volt-amperes
  • Basic concepts of equivalent circuit models for transformers
NEXT STEPS
  • Research the effects of magnetizing current on transformer performance
  • Study the equivalent circuit models used for power transformers
  • Learn about the implications of non-unity power factors in electrical systems
  • Explore methods for improving power factor in transformer applications
USEFUL FOR

Electrical engineers, power system analysts, and anyone involved in transformer design and performance optimization will benefit from this discussion.

fred2028
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PF is P / S in general. If the transformer is running at 80.1% of full load, the PF should stay the same right since

PF = 0.801P / 0.801S
= P / S

since if the transformer is running at 80.1% full load, the output S and output P would both be 80.1% right? So basically, no matter what load, the PF is constant since the percentage of full load of the transformer cancels out?
 
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The power factor not being exactly unity is due to what, exactly?

I'm trying to understand this. The units of S , are they volt-amperes?

Is the load considered purely resistive in all of this?

What is the equivalent circuit model you are using for your power transformers? Does this give you a clue?
 
fred2028 said:
PF is P / S in general. If the transformer is running at 80.1% of full load, the PF should stay the same right since

PF = 0.801P / 0.801S
= P / S

since if the transformer is running at 80.1% full load, the output S and output P would both be 80.1% right? So basically, no matter what load, the PF is constant since the percentage of full load of the transformer cancels out?

Hi Fred. What percentage (of it's full load value) do you think the magnetizing current would be when the transformer is running at 80% load current?
 

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