Power Loss in a 10kV, 5ohm Transmission Line

AI Thread Summary
To calculate power loss in a 10 kV transmission line with a resistance of 5 ohms while transmitting 10,000 kW, the formula P = I^2 * R is used. First, the current is determined using Ohm's Law, resulting in 2000 A. Plugging this value into the power loss formula gives a loss of 4 MW. This indicates that out of the 10 MW transmitted, 4 MW is lost due to resistance. Minimizing resistance in transmission lines is crucial for enhancing efficiency.
DB
Messages
501
Reaction score
0
-A transmission line has a resistance of 5 ohms. Calculate the power loss in the line when 10 000 kW are transmitted at 10 kV...

I don't know where to start, what formula am I supposed to use? I'm sure the second I find out its going to be soo easy, but any help would be apreciated.

Thanks in Advance
 
Physics news on Phys.org
DB said:
-A transmission line has a resistance of 5 ohms. Calculate the power loss in the line when 10 000 kW are transmitted at 10 kV...

I don't know where to start, what formula am I supposed to use? I'm sure the second I find out its going to be soo easy, but any help would be apreciated.
Use:

P = VI = I^2R where V is the voltage drop over the transmission line and I is the current it conducts, and R is the resistance of the line.
What is the current if the 10 kV line is conducting 10,000 kW (that is just P = VI)?

AM
 


To calculate the power loss in a transmission line, we can use the formula P = I^2 * R, where P is the power loss, I is the current, and R is the resistance. In this case, we are given the voltage (10 kV) and power (10,000 kW), but we need to find the current in order to use the formula. We can use Ohm's Law, V = I * R, to solve for the current.

10 kV = I * 5 ohms
I = 10 kV / 5 ohms
I = 2000 A

Now, we can plug in the current into the power loss formula.

P = (2000 A)^2 * 5 ohms
P = 4,000,000 W or 4 MW

Therefore, the power loss in the transmission line is 4 MW. This means that 10,000 kW (or 10 MW) of power is being transmitted, but 4 MW is being lost due to the resistance in the line. This highlights the importance of minimizing resistance in transmission lines to reduce power loss and improve efficiency.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top