Power loss in sinusoidal electric fields

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SUMMARY

The discussion centers on the derivation of the average power dissipation per unit volume in sinusoidal electric fields, specifically the equation P=(1/2)*J*E (W/m^3). The coefficient of 1/2 arises from the relationship between the root mean square (RMS) value of the electric field (Erms) and the peak value of the sinusoidal electric field. The earlier equation for differential power dissipation, dP= J*E (W/m^3), assumes a constant electric field, whereas the average power dissipation considers the sinusoidal nature of the electric field.

PREREQUISITES
  • Understanding of electromagnetics principles
  • Familiarity with sinusoidal waveforms
  • Knowledge of current density (J) and electric field (E)
  • Concept of root mean square (RMS) values
NEXT STEPS
  • Study the derivation of RMS values for sinusoidal functions
  • Explore the concept of loss tangents in electromagnetics
  • Investigate the relationship between current density and electric field in AC circuits
  • Review power dissipation equations in different electromagnetic contexts
USEFUL FOR

Students and professionals in electrical engineering, particularly those studying electromagnetics and power systems, will benefit from this discussion.

JerryG
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Homework Statement


In my electromagnetics book, in the section that talks about loss tangents, the equation for average power dissipation per unit volume is P=(1/2)*J*E (W/m^3). What does the coefficient of 1/2 come from? Earlier in the book, it gave the differential power dissipation dP= J*E (W/m^3)

Homework Equations


J = current density.
E= electric field.
 
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Is it possible that previously E was a constant value, and now E is the peak value of a sinusoid?
 
gneill said:
Is it possible that previously E was a constant value, and now E is the peak value of a sinusoid?

That's it. It's the Erms ^ 2 that gives the 1/2.
 

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