Power Series expansion of hyperbolic functions

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thanksie037
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Homework Statement



power series expansion of:

((cosh x)/(sinh x)) - (1/x)


Homework Equations



cosh x = (1/2)(ex + e-x)
sinh x = (1/2)(ex - e-x)

The Attempt at a Solution


what i have so far:

I simplified the first part of the eq to read :
e2x-1
e2x-1


now I am stuck. please help
 
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You simplified for it to be [tex]\frac{e^{2x}-1}{e^{2x}-1}[/tex]? Isn't that just 1?
 
I'm sorry that was a typo. Should I just expand both was like you would ex? how about the 1/x part?
 
I would and then hopefully things will cancel, for example what's the expansion for [tex]e^{2x} - 1[/tex]?
 
How do one usually find the taylor series of a given function?
now you have a function, what do you do? :rolleyes: