Predicting Fermi Surface from Chemical Formula

Click For Summary

Discussion Overview

The discussion revolves around predicting the Fermi surface of the compound LaFeAsO based on its chemical formula and the valence states of its constituent elements. Participants explore the relationship between the chemical composition, oxidation states, and the resulting band structure, with a focus on the implications for metallicity and electronic properties.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant questions the professor's assertion that band crossings can be predicted solely from the chemical formula, expressing confusion about the reasoning behind the emphasis on iron (Fe).
  • Another participant suggests that understanding the valence orbitals and their occupation is crucial for analyzing the compound's electronic structure.
  • A participant proposes that since Fe is close to half-filling, it may dominate the band structure, indicating high metallicity and lower binding energy for its 3d electrons.
  • There is a correction regarding the counting of electrons in the ions, with a focus on the importance of considering ionic states rather than neutral atoms.
  • Participants clarify the oxidation states of La, Fe, As, and O, with specific attention to how these states influence the filling of valence shells and the formation of bands.
  • One participant expresses uncertainty about the assumption of common oxidation states, questioning how these are determined in the context of solid-state physics.
  • A later reply emphasizes the significance of oxidation states in forming a neutral compound and discusses the implications for the electronic structure, particularly highlighting the role of partially filled d-orbitals in Fe.

Areas of Agreement / Disagreement

Participants exhibit a mix of agreement and disagreement regarding the oxidation states and their implications for the electronic structure. While some participants provide corrections and clarifications, there is no consensus on the initial assumptions about band structure predictions based solely on the chemical formula.

Contextual Notes

Participants note the importance of distinguishing between ionic and neutral states when discussing valence electrons. There are unresolved questions about the assumptions made regarding oxidation states and their relevance to predicting electronic properties.

tylerscott
Messages
28
Reaction score
0
Hi, I was hoping I could get some things cleared up. Recently my Solid State professor mentioned that we could simply, from the chemical formula, predict where the band crossings are going to be. For example, take LaFeAsO. Since La has a valency of +3, Fe of +3, As of -3, and O of -2, he deducted from the lattice (which is more or less cubic), that the band crossings are going to be primarily from the Fe. However, I'm completely lost as to why. Any help is appreciated!
 
Physics news on Phys.org
This is a mainly ionic compound. Did you pay attention in your chemistry class? Then you should be able to name the valence orbitals of these elements and their occupation in the ions. For which element in your list aren't they neither full nor empty?​
 
So, La is 5d1, Fe is 3d6, As is 4p3, and O is 2p4. So Fe is close to half filling. But, so is As and O. So can we just say the bandstructure will compose of mostly Fe because of the half filling? Therefore, it is highly metallic and also the binding energy of the 3d6 should be much smaller?
 
You didn't count well. Take in mind that these are ions.
 
So Fe is 3d8. La is 5d3. On the right track?
 
No. Neutral La has 5d1 6s2, so La 3+ has none. Neutral Fe has 3d6 4s2, so what do you get for Fe 3+?
 
I'm afraid I'm quite rusty in my chemistry here. So, Fe 3+ would be 3d5. However, I'm not sure where the 3+ for La is coming from (unless it's just because its a common oxidation state). How can one assume that the most common oxidation state is the right one to choose?
 
Solid state physics is in some respect inorganic chemistry specialized to molecules of infinite size. So you better polish your inorganic chemistry.
Lanthanum has almost exclusively oxidation state 3+ just like oxygen mostly 2-. Iron mostly 2+ or 3+ and arsenic 3-, 3+ or 5+.
The only reasonable combination to make this compound neutral is thus O 2-, As 3-, La 3+ and Fe 3+. Hence the valence shells on O and As are completely filled while the one of La is completely empty. If you form bands from these atomic states, they will be filled or empty, too. This leaves as the main suscpect only Fe whose d-orbitals are only partially filled and partially degenerate in a cubic environment (cf Ligand field theory).
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 19 ·
Replies
19
Views
9K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 1 ·
Replies
1
Views
109K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 21 ·
Replies
21
Views
6K