Pressure At Surface And Scale Height

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SUMMARY

The discussion focuses on calculating the scale height (λ) of a planet's atmosphere using pressure values at different altitudes. The user provides atmospheric pressure measurements at 6 km (0.5 P0) and 8 km (0.4 P0) and attempts to derive λ using the equation P(z) = P(0)e^(-z/λ). The user correctly sets up the equation but encounters confusion when manipulating logarithmic terms. The key takeaway is that the logarithmic transformation must be applied correctly to isolate λ without cancellation errors.

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  • Knowledge of logarithmic functions and their properties
  • Basic algebraic manipulation skills
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bobbles22
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Please can someone tell me if my thinking here is right...

I've got a planet with an atmospheric pressure at 6km of 0.5 P0 and at 8km of 0.4 P0 (P0 = pressure at the surface).

I want to work out the scale height of the atmosphere.

Given scale height = λ

and for height above surface = z

P(z)=P(0)e(-z/λ)

I could rearrange to show the pressure at the surface as:

P(0)=P(z)/e(-z/λ)

I could then use the relative pressure, assume P(0)=1 (as it will cancel out shortly) and height from each of the know quantities and set them equal to each other like this:

0.4/e(-8000/λ) = 0.5/e(-6000/λ)

A little mutliplication...

0.4 e(-6000/λ) = 0.5 e(-8000/λ)

Take the Log of both sides...

(-6000/λ) log 0.4 = (-8000/λ) log 0.5

But know I'm left with the λ cancelling out if I multiply both sides by λ. I'm sure I've gone wrong here somewhere. Probably something very simple. Can anyone advise? Have I made a simple mistake in my working or have I gone completely off the reservation and need to start again? I just need to end up with λ = xxx metres.

Thank you.
 
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hi bobbles22! :smile:
bobbles22 said:
0.4 e(-6000/λ) = 0.5 e(-8000/λ)

Take the Log of both sides...

(-6000/λ) log 0.4 = (-8000/λ) log 0.5

nooo :wink:

(-6000/λ) + log 0.4 = (-8000/λ) + log 0.5 :smile:
 

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