Preventing Small Math Mistakes - Advice Appreciated

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Small math mistakes often stem from rushing through problems and not reviewing work carefully. To minimize errors, it's crucial to slow down, pace oneself, and check each step immediately after completing it. Treating homework like a test can help reinforce precision and attention to detail. Organizing calculations clearly and methodically is essential for reducing mistakes. Ultimately, recognizing that even experienced individuals make errors can help maintain perspective during the learning process.
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I know there is probably not an easy answer to my question but I still wanted to ask.
Anytime I take a math test I always make a mistake with a minus sign, domain issue, or something small that will lead me to the wrong answer.
Are there any sure ways to prevent me from doing this? I study math all the time yet I still make dumb mistakes... I think I tend to read over the problem to quickly.

Anyways advice would be appreciated...
 
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Precision, precision, precision! Math is above all, very precise. All I can say is be very careful to review every step.
 
When I was a freshman, I used to make similar mistakes. I would rush through tests and finish usually with 5 to 10 minutes left. Then I'd go back and check my work. This didn't work very well because it's hard to look closely enough on the second round to spot minor errors. I decided I'd be better off slowing down and pacing myself to avoid making dumb mistakes. After each step, I went back and reviewed it right then and there to see if I made a silly algebra mistake. It worked. The occasional error would occasionally slip by, but they didn't happen at nearly the frequency as before.
 
Thank you for the advice.. I am going to try and treat my homework as a test hopefully that will prepare me aswell..
Ill work on my precision and looking at each step carefully while doing my hm

thank yoiu.
 
Checking your answers is an exercise in critical thinking. You must not assume that you did anything correctly! Try to be as objective as possible when checking your answers. This is difficult to do when reviewing "routine" concepts/computations, but it is crucial to catching your mistakes.

Also, you need to be extremely careful with how you organize your work. Write clearly, and have a consistent method for organizing your calculations. I can't stress enough how important being methodical and organized has been for me.

Lastly, some of my brightest professors have made mistakes, either in lecture notes or problem sets. It's something that will happen from time to time. :smile:
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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