- #1
Russell E. Rierson
- 384
- 0
Here is a tentative conjecture that needs to be tested.
[P! + P]/P^2 = INTEGER
if and only if P is a prime number
P! is P factorial, e.g. 3*2*1 , 5*4*3*2*1 , 7*6*5*4*3*2*1, etc...
[P! + P]/P^2 = INTEGER
if and only if P is a prime number
P! is P factorial, e.g. 3*2*1 , 5*4*3*2*1 , 7*6*5*4*3*2*1, etc...