Principle of Moments: Balancing a Meter Rule

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SUMMARY

The discussion centers on the application of the Principle of Moments to balance a meter rule. Given a mass of 5 kg placed 40 cm from the pivot, the required mass to balance the rule at 30 cm from the pivot is calculated to be 6.66 kg. The equation used is M1 * G * D1 = M2 * G * D2, where G is the acceleration due to gravity (9.8 m/s²). The solution confirms that the calculated mass of 6.66 kg is correct.

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Homework Statement


A metre rule is balanced at the 50 cm mark. If a mass of 5kg is placed 40 cm from the pivot at one end, what mass must be placed 30 cm from the pivot on the other end to balance the rule?


Homework Equations



M1 * G * D1 = M2 * G * D2



The Attempt at a Solution


M1 = 5kg
M2 = ?
D1 = 40 cm
D2 = 30 cm
G = 9.8

Therefore 5 * 9.8 * 40 = M2 * 9.8 * 30
= (5 * 9.8 * 40)/9.8 * 30
M2 = 6.66kg Is this correct?
 
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Yes.
 
01010011 said:

Homework Statement


A metre rule is balanced at the 50 cm mark. If a mass of 5kg is placed 40 cm from the pivot at one end, what mass must be placed 30 cm from the pivot on the other end to balance the rule?


Homework Equations



M1 * G * D1 = M2 * G * D2



The Attempt at a Solution


M1 = 5kg
M2 = ?
D1 = 40 cm
D2 = 30 cm
G = 9.8

Therefore 5 * 9.8 * 40 = M2 * 9.8 * 30
= (5 * 9.8 * 40)/9.8 * 30
M2 = 6.66kg Is this correct?
Yes.
 

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