Gravity and Mass Homework: 0.000000364kg

[woaini]

Homework Statement

A 3.0 kg spherical flask is placed on a scale and balanced. Then a ball with a mass of 5775 kg is placed directly underneath the flask, resulting in a center-to-center distance of 56.9 cm. How much mass would have to be added to the other side of the scale in order to re-balance it?

G = 6.67 x 10^-11 Nm^2/kg^2
m1=3kg
m2=5775kg
r=0.569m

Homework Equations

(G*m1*m2)/r^2 = mg

The Attempt at a Solution

m=$\frac{G*m1*m2}{r^2*g}$

m=$\frac{(6.67*10^-11)*(3)*(5775)}{(.569)^2*(9.81)}$

m=0.000000364 kg

 

[nasu]

Do you have a question?

 

[woaini]

Do you have a question?

Did I setup the equation right?

 

[nasu]

It looks OK to me.