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Homework Statement
A 3.0 kg spherical flask is placed on a scale and balanced. Then a ball with a mass of 5775 kg is placed directly underneath the flask, resulting in a center-to-center distance of 56.9 cm. How much mass would have to be added to the other side of the scale in order to re-balance it?
G = 6.67 x 10^-11 Nm^2/kg^2
m1=3kg
m2=5775kg
r=0.569m
Homework Equations
(G*m1*m2)/r^2 = mg
The Attempt at a Solution
m=[itex]\frac{G*m1*m2}{r^2*g}[/itex]
m=[itex]\frac{(6.67*10^-11)*(3)*(5775)}{(.569)^2*(9.81)}[/itex]
m=0.000000364 kg