Probabibility Independent events

In summary, the probability of getting a queen in my second draw given that the first card was a spade, independent events, is 1/13.f
  • #1

Homework Statement



Why is it that the probability of getting a queen in my second draw given that the first card was a spade, independent events? What if the first card drawn was the queen of spades?

Homework Equations


P(A and B)=P(A)P(B)
 
  • #2
How many queens are there in a deck of cards after drawing one non-queen card?

How many cards are there in the deck after drawing your first card?
 
  • #3
What if the first card drawn was the queen of spades?
What if it was another spade?
 
  • #4

Homework Statement



Why is it that the probability of getting a queen in my second draw given that the first card was a spade, independent events? What if the first card drawn was the queen of spades?

Homework Equations


P(A and B)=P(A)P(B)

It's clear that the first card and the second card are not independent. The probability that the second card is a spade depends on whether the first card is a spade etc.

But, does the probability that the second card is a queen depend on the suit of the first card?

You can try to resolve the issue as follows:

Before we start we know that the probability that the second card is a queen is 1/13.

Then, we draw the first card and I look at it and tell you it's a spade.

Now, is the second card more likely or less likely to be a queen? Or, is it still 1/13?

What if the first card was a diamond? Or a heart? Or a club?

Perhaps it's clear, therefore, that the denomination of the second card does not depend on the suit of the first card?

Finally, however, I would recommend checking this out using conditional probabilities. It's a good exercise in any case.
 

Suggested for: Probabibility Independent events

Replies
7
Views
662
Replies
2
Views
668
Replies
1
Views
1K
Replies
1
Views
733
Replies
7
Views
1K
Replies
3
Views
1K
Back
Top