Probability a five-card contains the ace of hearts

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The probability of drawing a five-card hand that contains the ace of hearts can be calculated using combinations. The formula involves selecting the ace of hearts and then choosing four additional cards from the remaining 51 cards. The calculation is expressed as 1 multiplied by the combination of 51 cards taken 4 at a time, divided by the combination of 52 cards taken 5 at a time. This approach simplifies the problem and provides a clear method for determining the desired probability. The final expression is 1*C(51,4)/C(52,5).
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Homework Statement


What is the probability that a five-card contains the ace of hearts?

Homework Equations


P(E)=|E|/|S|
P(E_{1}\bigcup E_{2})=P(E_{1})+P(E_{2}) + P(E_{1}\bigcap E_{2})

The Attempt at a Solution


The number of ways to choose 5 cards from 52*the numbers of ways to get an ace from five of those?
C(52,5)C(5,1)
 
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mmm, try:

number of ways to choose ace of hearts*number of ways to choose the other 4 cards/number of ways to choose 5 cards from 52.

1*c(51,4)/c(52,5)

that seems better to me.
 
That looks better, thank you very much.
 
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