1. The problem statement, all variables and given/known data A particle is confined between rigid walls separated by a distance L=0.189. The particle is in the second excited state (n=3). Evaluate the probability to find the particle in an interval of width 1.00 pm located at a)x=0.188nm b)x=0.031nm c)x=0.79nm What would be the corresponding results for a classical particle 2. Relevant equations P(X)=abs(ψ(x)^2)dx ψ(x)=(√2/L)*(sin(nπx/L) 3. The attempt at a solution for part a P(x)=(2/.189)*(sin(3π(.0188))/.189))^2=.28/m I know the probability is just a matter of squaring ψ but my answer is way off. The got 2.63*10^-5 for part A. My first through was why does my answer have units of 1/m. I'm guessing i should multiply by dx. I thought this may be 1.00 pm but simply multiplying my answer by 10^-12 wont get the job done. Am i getting some variables mixed up here?