- #1

Data&Stuff

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First question :

I want to know how can I find the probability of landing on each different spot from one to ten ? The probability of the coin is pretty simple, but I need help . please help me :(

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- Thread starter Data&Stuff
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- #1

Data&Stuff

- 3

- 0

First question :

I want to know how can I find the probability of landing on each different spot from one to ten ? The probability of the coin is pretty simple, but I need help . please help me :(

- #2

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- 3,305

The rules of the game are not quite clear to me... For example: what happens if I roll a 6?

- #3

Data&Stuff

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I just want to know how to find the probability of finishing the game and rolls.

- #4

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[tex]\left(\begin{array}{cccccccccc}

0 & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & 0 & 0 & 0\\

0 & 0 & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & 0 & 0\\

0 & 0 & 0 & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & 0\\

0 & 0 & 0 & 0 & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6}\\

0 & 0 & 0 & 0 & 0 & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{3}\\

0 & 0 & 0 & 0 & 0 & 0 & \frac{1}{6} & \frac{1}{6} & \frac{1}{6} & \frac{1}{2}\\

0 & 0 & 0 & 0 & 0 & 0 & 0 & \frac{1}{6} & \frac{1}{6} & \frac{2}{3}\\

0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & \frac{1}{6} & \frac{5}{6}\\

0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1\\

0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 1\\

\end{array}\right) [/tex]

With that matrix, you can easily calculate that the probability that you finish the game is 1. But that is probably not the answer that you want... Maybe you should ask the question: what is the probability that I finish the game in 4 turns (or something likely).

The probability of finishing the game in 1 turn is 0

The probability of finishing the game in 2 turns is 0.27

The probability of finishing the game in 3 turns is 0.74

The probability of finishing the game in 4 turns is 0.94

The probability of finishing the game in 5 turns is 0.99

The probability of finishing the game in 6 turns is 0.99

The probability of finishing the game in 7 turns is 0.99

The probability of finishing the game in 8 turns is 0.99

The probability of finishing the game in 9 turns is 1

Of course, this probabilities are without the "hurdles" every 3 places. I did not factor them in because you did not yet explain what they do...

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