Probability Involving AND and OR

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The discussion revolves around calculating the probability that a randomly selected student from Roanoke College is both from out of state and lives on campus. Given that 1/3 of students live off campus, 5/9 are from Virginia, and 3/4 are either from out of state or live on campus, the solution involves using the formula for probabilities involving AND and OR. The calculation results in a probability of 13/36 for a student being out of state and living on campus. A minor correction was noted regarding the phrasing "out off state," which should be "out of state." The solution was confirmed as correct by another participant.
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Hi folks,

Homework Statement


At Roanoke College it is known that 1/3
of the students live off campus. It is also known that 5/9
of the students are from within the state of Virginia and that 3/4
of the students are from out of state or live on campus. What is the
probability that a student selected at random from Roanoke College is from out
of state and lives on campus?


Homework Equations



-

The Attempt at a Solution



It should yield:
P(out off state OR lives on campus) = P(out off state) + P(lives on campus) - P(out off state AND lives on campus)
thus
P(out off state AND lives on campus)
= P(out off state)+P(lives on campus)-P(out off state OR lives on campus)
=(1-5/9)+(1-1/3)-(3/4)
=4/9 + 2/3 - 3/4
=13/36
Is this correct?

-derivator
 
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Yes.
 
thanks
 
The phrase should be "out of state", not "out off state".
 
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