Probability of Ordering Blue, White, and Green Cars | Homework Question Help

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The discussion focuses on calculating the probability of ordering one blue, one white, and one green car from a selection of blue, white, black, and green cars, all in equal demand. The participant is struggling to find the correct approach and has attempted various techniques, including calculating the probability of not ordering black cars and using "runs" of events, but has not succeeded. They have identified that there are 24 distinct 3-combinations of the four colors, questioning how to determine the numerator for the probability calculation. The conversation emphasizes the need to consider repetitions in combinations for accurate probability assessment. Overall, the thread highlights the challenges of solving probability problems in combinatorial contexts.
Iyafrady
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I need help with this homework question:
The colors blue,white,black, and green are in equal demand for a type of car.Three succesive orders are placed for this type of car.Find the probability of the following events.
a)one blue,one white, and one green are ordered.
 
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You should post under the HW section, and indicate your attempt to solve it.
 
if anyone could just help me get started I am shure i could figure it out.Ive tried several techniqies with no succes, the answer in the book is .09375
 
What techniques did you try?
 
i tried to find the probability that a black wasnt ordered and subtract that from 1 but i didnt get the right answer.I also tried doing a calculation were you find the "runs" of an event but that also failed.Aswell as other techniques i can't remember.
 
Iyafrady said:
i tried to find the probability that a black wasnt ordered and subtract that from 1 but i didnt get the right answer.I also tried doing a calculation were you find the "runs" of an event but that also failed.Aswell as other techniques i can't remember.
How many different 3-combinations of 4 colors are there?
 
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ok there are 24 distinct 3-combinations, and that would be the denominator??What about the numerator?maybe I've been lookaing at this problem too long..:-(
 
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For the denominator, you should allow for repetitions:

all black = {B, B, B, B} or all blue = {b, b, b, b} or 2 white, 2 green = {w, w, g, g} = {w, g, w, g} = {w, g, g, w} = etc...
 
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