Probability of winning in a competition (first, second and third)

Click For Summary
SUMMARY

The probability of both contestants A and B winning in a competition with seven participants is calculated using combinatorial methods. The initial calculation of 3/7 x 2/6 yields a probability of 1/7 for A being selected first and B second. However, this approach overlooks the scenario where B is selected first and A second, leading to an additional 1/7 probability. The correct total probability for A and B winning is therefore 2/7, accounting for both selection orders.

PREREQUISITES
  • Understanding of basic probability concepts
  • Familiarity with combinatorial counting methods
  • Knowledge of permutations and combinations
  • Ability to analyze probability scenarios with multiple outcomes
NEXT STEPS
  • Study combinatorial probability in-depth, focusing on permutations and combinations
  • Learn about conditional probability and its applications in competitions
  • Explore advanced probability topics such as Bayes' theorem
  • Practice solving probability problems involving multiple participants and outcomes
USEFUL FOR

Students studying probability theory, educators teaching combinatorial methods, and anyone interested in competitive analysis and decision-making under uncertainty.

desmond iking
Messages
284
Reaction score
2

Homework Statement



A and B are together with 5 other contestants take part in a competition. The winners are champion, first -runner up and second- runner up. Find the probability that A and B are winner

my working is 3/7 x 2/6= 1/7 the ans is correct.

but by doing so i assume A is selected first. then B is selected after this. why there's no another probability that i select B first , then i select A . which is also 3/7 x 2/6= 1/7.. so by adding 2 of the probability , i have 1/7 + 1/7 = 2/7

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
By doing the 3/7 x 2/6 you are counting both A being selected first as well as B being "selected" first
think about it
A 1st -> B 2nd or 3rd
A 2nd -> B 1st or 3rd
A 3rd -> B 1st or 2nd so those are A being selected first what if we did B first?

B 1st > A 2nd or 3rd but look both combinations here are counted already B1 A2 was counted in the 2nd row and B1 A3 was counted in the 3rd

hope that helps
 
  • Like
Likes   Reactions: 1 person

Similar threads

Replies
1
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
Replies
31
Views
7K
Replies
2
Views
1K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K