A trial consists of tossing two dice. The result is counted as successful if the sum of the
outcomes is 12. What is the probability that the number of successes in 36 such trials is
greater than one? What is this probability if we approximate its value using the Poisson
The Attempt at a Solution
So first we must calculate the probability that the dice will add up to 12. The only possible way for this to happen is if they are both showing a 6.
So multiplying the chances of a 6 showing up per dice we get 1/6 * 1/6, or 1/36. There is a 1/36 chance of seeing 12.
This is where i get confused. How do we calculate the probability that 36 trials will give us more than 1 event where the dices read 12? I'm also confused about the Poisson Random Variable part.