- #1

rooski

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## Homework Statement

A trial consists of tossing two dice. The result is counted as successful if the sum of the

outcomes is 12. What is the probability that the number of successes in 36 such trials is

greater than one? What is this probability if we approximate its value using the Poisson

random variable?

## The Attempt at a Solution

So first we must calculate the probability that the dice will add up to 12. The only possible way for this to happen is if they are both showing a 6.

So multiplying the chances of a 6 showing up per dice we get 1/6 * 1/6, or 1/36. There is a 1/36 chance of seeing 12.

This is where i get confused. How do we calculate the probability that 36 trials will give us more than 1 event where the dices read 12? I'm also confused about the Poisson Random Variable part.