Probability that Bill told the truth problem

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To determine the probability that Bill told the truth given Harry's statement, we analyze the conditional probabilities involved. Bill tells the truth 50% of the time, while Harry tells the truth 66.67% of the time. There are four possible scenarios based on their truth-telling rates: Harry telling the truth when Bill tells the truth, Harry lying when Bill tells the truth, and similar outcomes when Bill lies. Using Bayes' theorem and the provided probabilities, the calculation reveals that the probability of Bill telling the truth, given Harry's confirmation, is approximately 75%. Understanding these probabilities is crucial for solving similar conditional probability problems.
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Bill tells the truth one-half of the time and Harry tells the truth two-thirds of the time. Bill says something, and Harry, who knows whether Bill told the truth, says, "Bill just told the truth". What is the probability that Bill told the truth?

Let:
B = Bill told the truth
B' = Bill lied
H = Harry told the truth
H' = Harry Lied

P(B) = .5
P(B') = .5
P(H) = 2/3
P(H') = 1/3


So there should be 4 possible outcomes.. (H|B), (H'|B), (H|B'), (H'|B').

I know that there is an equation for each of these, like P(H|B) = P(H|B)/P(B|H) or something like that I'm just not sure which equation to use. Please help! Thanks!
 
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http://en.wikipedia.org/wiki/Conditional_probability" may help.
 
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I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
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