What is the Probability of A' n B' Given A' and A, B, and A n B?

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The discussion focuses on calculating the probability P(A' n B' | A') using known probabilities P(A), P(B), and P(A n B). It establishes that P(A u B) can be derived from the formula P(A) + P(B) - P(A n B). The calculation simplifies to P(A' n B' | A') = [1 - P(A u B)] / P(A'). The final expression is confirmed as [1 - P(A u B)] / [1 - P(A)]. The discussion concludes with a verification of the derived formula's correctness.
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Given P(A), P(B), and P(A n B) . Find the P(A' n B' | A')
We know P(AuB) = P(A)+P(B)- P(A n B)
Then
P(A' n B'|A') = P(A' n B' n A' ) / P(A') = P(A' n B') / P(A') = P(A u B)' /P(A') = [1-P(A u B) ]/ P(A') =
[1-P(A u B)] / [1-P(A)] Correct?
 
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