- #1
Iftekhar Uddin
- 7
- 0
What I Think I Understand: ΔV = Ed (d being dstance) and that V = kq/r
please correct me if I'm misunderstanding those.
What I need to know: When E = 0, what happens to the electric potential? and vice versa.
Me Working it out: So if i use the first equation up here, If E = 0, then electric Potential = 0. Even with the second equation wouldn't I compare the net electric field with the net potential at a point? If so, then my answer remains the same. Either my equations are wrong or I'm really misunderstanding a simple concept. I may just be reaching my burnout point with physics right now. (I'm a few days in of focused physics studying and I can't wrap my head around simple concepts like this anymore.)
please correct me if I'm misunderstanding those.
What I need to know: When E = 0, what happens to the electric potential? and vice versa.
Me Working it out: So if i use the first equation up here, If E = 0, then electric Potential = 0. Even with the second equation wouldn't I compare the net electric field with the net potential at a point? If so, then my answer remains the same. Either my equations are wrong or I'm really misunderstanding a simple concept. I may just be reaching my burnout point with physics right now. (I'm a few days in of focused physics studying and I can't wrap my head around simple concepts like this anymore.)