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Problem about rate of change (multivariable calculus)

  1. Feb 23, 2013 #1
    1. The problem statement, all variables and given/known data
    Let T = f(x, y, z), where dx/dt = 4, dy/dt = 4 and dz/dt = -3
    Calculate dT/dt if dT/dx = 4, dT/dy = 7 and dT/dz = 9


    2. Relevant equations
    dT/dt = ∂T/∂x (dx/dt) + ∂T/∂y (dy/dt) + ∂T/∂z (dz/dt)


    3. The attempt at a solution
    I tried to get an explicit formula for T. I thought that, if dT/dx = 4, then T = 4x + c. Similarly, T = 7y + c and T = 9z + c. If i add the above expressions, I get:

    3T = 4x + 7y + 9z + C, so, T would be T = 4x/3 + 7y/3 + 3z + C, and I could use the chain rule and just substitute dx/dt and so on...

    Is my reasoning fine?
     
  2. jcsd
  3. Feb 24, 2013 #2
    Why do you need to do anything about T?

    You have the equation for dT/dt, and you know the values of everything on its right-hand side.
     
  4. Feb 24, 2013 #3

    HallsofIvy

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    First, you can't get an explicit expression for T, there are infinitely many possibililties. But you don't need that, just the "chain rule"":
    [tex]\frac{dT}{dt}= \frac{\partial T}{\partial x}\frac{dx}{dt}+ \frac{\partial T}{\partial y}\frac{dy}{dt}+ \frac{\partial T}{\partial z}\frac{dz}{dt}[/tex]
     
  5. Feb 24, 2013 #4
    But I need ∂T/∂x and I have dT/dx = 4 (same for the others). Don't tell me ∂T/∂x = dT/dx, because I'm gonna cry
     
  6. Feb 24, 2013 #5
    Using d when you have a function with more than one variable is not correct notation. ∂T/∂x is the correct notation.
     
  7. Feb 24, 2013 #6
    Omg you are right. My teacher wrote it like dT/dx, and I never realized he wrote it wrong. Thank you for your help guys
     
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