Problem with a logarithmic rule

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The discussion focuses on understanding logarithmic rules, particularly how inverting numbers and changing signs affects logarithmic expressions. It highlights the property that ln(a^b) equals b*ln(a) and demonstrates that ln(A/B) can be rewritten using the logarithmic identity ln(A) - ln(B). By multiplying the fraction by -1, the expression transforms into ln((N0/N)^-1), which simplifies to ln(N/N0). This manipulation confirms that the logarithmic properties hold true, leading to the final expression for time, t, in terms of N and N0. The explanation clarifies the logarithmic rules effectively.
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Please could some one help me with the rules of logarithms to understand why inverting the numbers in the bracket and change the minus sign to a plus sign gives the same result?

Thank you
 
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ln(a^b)=b*ln(a)
Try b=-1
 
ln(A/B) = ln(A) - ln(B) = -[ln(B) - ln(A)] = -ln(B/A)
 
for the equation on the right: t= ( ln (N0/N) ) / λ:

if you multiply top and bottom of the fraction by -1 you get

t= (-1 ln (N0/N)) / -λ

You have -1 ln (N0/N) which is equal to ln( (N0/N)^-1 ) by the power rule. The (N0/N)^-1 inside the log flips to (N/N0) from the negative exponent and you get:

t= ( ln (N/N0) ) / -λ.
 
Fantastic thanks to you all
 
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