Problem with Energy Dissipation

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The discussion revolves around calculating the energy dissipated when a steel ball is dropped into sand. The initial potential energy is calculated using the formula mgh, resulting in 507 J. However, the user realizes that the total distance the ball travels, including the 0.5 m it sinks into the sand, must be considered for accurate energy dissipation. It is clarified that there is indeed a change in gravitational potential energy when the ball moves downward in the sand. The conversation emphasizes the importance of accounting for the entire distance traveled in energy calculations.
sojo
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Homework Statement



A 4.70-kg steel ball is dropped from a height of 11.0 m into a box of sand and sinks 0.500 m into the sand before stopping. How much energy is dissipated through the interaction with the sand? Express answer using three significant digits.

Homework Equations


Potential Energy = mhg
Mechanical Energy = (1/2)mv^2

The Attempt at a Solution


I thought that the energy dissipated would be equal to the potential energy at the start of the problem. So I found the initial potential energy with the equation mgh = (4.7)(11)(9.8) = 507 However, I submitted this answer and the program said it was incorrect.
 
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Hello. Welcome to PF!

What is the total distance the ball travels vertically?
 
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I guess it falls 11.5 m including the distance in the sand. Do I include the distance in the sand?
 
Is there any change in gravitational potential energy when the ball moves 0.5 m downward in the sand?
 
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Yeah there is. That makes a lot of sense. Thanks for your help!
 
OK. Hope it works out now.
 
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