carpelumen said:Homework Statement
A magnet of mass 0.10 kg is dropped from rest and falls vertically through a 35.0 cm copper tube. Eddy currents are induced, causing the copper to warm up. The speed of the magnet as it emerges from the tube is 1.50 m/s. How much heat energy is dissipated to the environment?
Homework Equations
E = mgh
The Attempt at a Solution
h = 35 cm --> .35 m
E = (.10 kg) * (9.81) * (.35 m) = .3433 J
Is the equation incorrect?
What happens to the P.E. that you have just calculated the magnet loses?carpelumen said:Homework Statement
A magnet of mass 0.10 kg is dropped from rest and falls vertically through a 35.0 cm copper tube. Eddy currents are induced, causing the copper to warm up. The speed of the magnet as it emerges from the tube is 1.50 m/s. How much heat energy is dissipated to the environment?
Homework Equations
E = mgh
The Attempt at a Solution
h = 35 cm --> .35 m
E = (.10 kg) * (9.81) * (.35 m) = .3433 J
Is the equation incorrect?
Jakob Weg said:An illustrative experiment on this issue
That's the kinetic energy (k.e.) that would have developed in the absence of the copper tube. What was the k.e. with the tube?carpelumen said:Homework Statement
A magnet of mass 0.10 kg is dropped from rest and falls vertically through a 35.0 cm copper tube. Eddy currents are induced, causing the copper to warm up. The speed of the magnet as it emerges from the tube is 1.50 m/s. How much heat energy is dissipated to the environment?
Homework Equations
E = mgh
The Attempt at a Solution
h = 35 cm --> .35 m
E = (.10 kg) * (9.81) * (.35 m) = .3433 J
Is the equation incorrect?
Heat energy dissipation occurs when the kinetic energy of the falling magnet is converted into thermal energy, causing the magnet to lose speed and eventually come to a stop.
The main factors that contribute to heat energy dissipation in a falling magnet include the strength of the magnetic field, the mass of the magnet, and the material it is falling through.
No, heat energy dissipation is a natural and unavoidable process that occurs when a magnet falls through a medium.
The rate of heat energy dissipation can be calculated using the equation Q = mcΔT, where Q is the heat energy dissipated, m is the mass of the magnet, c is the specific heat capacity of the medium, and ΔT is the change in temperature.
Yes, understanding heat energy dissipation in falling magnets is important for applications such as designing electromagnetic brakes and studying the behavior of magnets in different environments.