Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Problem with gravitation field perpendicular vector.

  1. Nov 22, 2018 #1
    since it is known that ##\vec{A_\perp} = -{mG \over R^2}## why did the professor write it as ##\vec{A_\perp} = {- R G \rho \over 3}## for perfect sphere with perfect mass distribution ? Shouldn't it be ##\vec{A_\perp} = -{4 \over 3} \pi R G \rho##? I need help thanks.
    Last edited: Nov 22, 2018
  2. jcsd
  3. Nov 22, 2018 #2

    Doc Al

    User Avatar

    Staff: Mentor

    If I understand your question, shouldn't that be a 4/3 instead of a 4? (But I agree that your professor's version seems off.)
  4. Nov 22, 2018 #3
    Sorry got it off by a bit there. fixed
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?