Problem with Sturm-Liouville equation

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SUMMARY

The discussion focuses on converting a general differential equation into the Sturm-Liouville form. The equation presented is of the type a(x)y'' + b(x)y' + [c(x) + (LAMBDA)d(x)]y = 0. A key insight provided is that if b(x) equals a'(x), the equation is already in Sturm-Liouville form. If not, it is necessary to multiply by a function μ(x) to achieve the desired form, leading to the differential equation a'(x)μ(x) + a(x)μ'(x) = b(x)μ(x).

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Hi there :smile: .
I'm having troubles at a point in one Sturm-Liouville problem .

I am trying to convert a generation eqn to the form of a Sturm-Liouville equation. The equation's form is as follows (where a(x),b(x),c(x),d(x) are arbitrary functions):

a(x)y'' + b(x)y'(x) + [c(x) + (LAMBDA)d(x)]y(x) = o

I begin by formatting in y'' + ... form. How do I proceed from here, please?

Ciao,

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If b(x) = a'(x) your equation is in Sturm-Liouville form...
 
If not, then you need to multiply by some \mu(x) so that it is:
a(x)\mu(x)y'' + b(x)\mu(x)y'(x) + [c(x) + (\lambda(x))d(x)]\mu(x)y(x) = 0

With a'\mu(x)+ a\mu'(x)= b(x)\mu(x). That gives you a simple differential equation for \mu(x).
 

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