Producing H_{2} Gas: Na + H_{2}O Reaction

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To determine the volume of hydrogen gas produced from the reaction of sodium with water, it is essential to calculate the number of moles of H2 generated. The balanced equation indicates that 2 moles of Na yield 1 mole of H2, meaning that 1.74 moles of Na will produce 0.87 moles of H2. The ideal gas law can then be applied to find the volume of H2 at the specified conditions of 280 K and 96 kPa. It is crucial to consider stoichiometric coefficients in these calculations for accurate results. Understanding stoichiometry is key to solving such chemical reaction problems effectively.
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1. How many liters of hydrogen gas will be produced at 280 K and 96 kPa if 1.74 of Na reacts with excess water according to the following equation.

2Na + 2H_{2}O \rightarrow2NaOH + H_{2}


Im gussing I am going to have to find the number of moles of H_{2} before I can do anything.

So I am thinking that since there is 1.74 mol of Na that is going to be the number of moles of H_{2}. Is that right?
 
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Use [noparse] and [/noparse] tags to format subscripts and superscripts (so [noparse]H3O+[/noparse] yields H3O+) - don't use inline LaTeX for formatting single characters.

You are wrong, but not far from the correct answer. You forgot to take stoichiometric coefficients into account. Please read about stoichiometric calculations.
 
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