The discussion focuses on applying the product rule to find the derivative of the product of two functions at a specific point. Given the values f(2) = 3, f'(2) = 5, g(2) = -1, and g'(2) = -4, the derivative (fg)'(2) is calculated using the formula (fg)'(x) = f'(x)g(x) + g'(x)f(x). Substituting the known values, (fg)'(2) equals 5 * (-1) + (-4) * 3, resulting in (fg)'(2) = -5 - 12 = -17.
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So you know the product rule:HerroFish said:Homework Statement
If f(2) = 3, f'(2) = 5, g(2) = -1, g'(2) = -4, find (fg)'(2).
Homework Equations
if F(x) = f(x)g(x)
F'(x) = f'(x)g(x) + g'(x)f(x)
The Attempt at a Solution
I have no idea how to attempt his question :(