Projectile Launched from the moon

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A projectile launched vertically from the Moon at 1380 m/s will reach an altitude where its speed is two-thirds of its initial value, approximately 920 m/s. The key difference between the Moon and Earth affecting this scenario is the Moon's lower gravitational acceleration, which is about 1/6th that of Earth's. This lower gravity means the projectile will ascend higher before its speed decreases significantly. The principles of energy conservation and kinematics apply similarly on both celestial bodies, but the calculations differ due to the varying gravitational forces. Understanding these differences is crucial for solving projectile motion problems on the Moon compared to Earth.
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Question: A projectile is launched vertically from the surface of the Moon with an initial speed of 1380 m/s. At what altitude is the projectile's speed two-thirds its initial value?

I don't really know where to start there is so little information. We went over escape velocity in class, but I don't think this is it.
 
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Could you solve this problem if it were on the earth?

If so what is the difference between the Earth and moon?
 
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