Projectile Motion Ball Drop: Solving for Initial Velocity with Given Angles

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SUMMARY

The discussion focuses on calculating the initial velocity (V0) of a ball dropped onto a step, which rebounds at a 15-degree angle with the vertical. The ball's velocity just before bouncing (VB) forms a 12-degree angle with the vertical, and the relevant equations include X = Vt and Y = Vt - 0.5gt². The key equation utilized is Vy(t)² = Vy0² + 2g(y(t) - y0), incorporating a 0.2m vertical displacement to solve for V0.

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Homework Statement


A Ball is dropped onto a step at point A and rebounds with a velocity Vo at an angle 15 degrees with the vertical. Determine the value of V0 knowing that just before the ball bounces at Point B its velocity VB forms an angle of 12 degrees with the vertical.

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Homework Equations



X = Vt
Y = Vt - 0.5gt2

The Attempt at a Solution



X = (VoSin15)t
Y = (VoCos15)t -0.5gt2

I am not sure how to make use of the other information provided.
 
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The most relevant equation:

Vy(t)^2 = Vy0^2 + 2g (y(t) - y0)

because we need to use the 0.2m y-displacement.

Also noteworthy:
Vx0 = V0 sin(15)
VxT = VT sin(12)
Vx0 = VxT
 

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