Projectile Motion (ignore previous thread)

[ch3570r]

Im trying to figure out this problem, but I am not sure if I have the equation(s) I need.

"A ball is thrown horizontally out the window of a building with a velocity of 8.0 m/s from a height of 2500 m. How far from the base of the building will the ball land?"

a) 54 m
b) 60 m
c) 90 m
d) 115 m
e) 180 m

The equations I have for the X value (distance in X) include the following:
Vx = ▲x/▲t
▲X = V0 * ▲t
Vfx^2 = Vix^2

Is this all I need to find the answer? Or am I missing some equation(s)?

 

[radou]

You need to find the time the ball traveled. You can find it from the equation of displacement in the y-direction.

 

[ch3570r]

ok. I found the equation y = y0 + Vy0t - 1/2(gt^2)

I solved for t, which came to be 22.6. Then I used x = x0 + Vx0t, which is 8 * 22.6, which comes out to 180.8.

Seems right...

 

[radou]

Yes, it does.