Projectile motion of a baseball problem

In summary, the problem is asking for the time the ball was in the air and the height it reached before being caught. Using the formula for projectile motion in the y direction, the correct calculation for the time in the air is 4.32 seconds. However, the calculation for the height reached was incorrect due to a double negative in the formula. After correcting this mistake, the correct height reached is approximately 9.7 meters.
  • #1
princesspriya
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0

Homework Statement


a baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23.0m/s. If the ball was caught 42 m from the thrower, how long was it in the air? how high did the ball travel before being caught?

Homework Equations




The Attempt at a Solution



using x=(VicoxA)t --> 42/(23*cos25) i got 4.32
and than using y=(23*sin25)4.32+1/2(-9.81)(4.32)^2 i got -49.5 >>y=(VisinA)t+1/2a(t)^2)
but in the back of the book it says its wrong so can someone please tell me what i did wrong?
 
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  • #2
using x=(VicoxA)t --> 42/(23*cos25) i got 4.32
and than using y=(23*sin25)4.32+1/2(-9.81)(4.32)^2 i got -49.5 >>y=(VisinA)t+1/2a(t)^2)
but in the back of the book it says its wrong so can someone please tell me what i did wrong?[/QUOTE

The formula for projectile motion is the Y direction is going to be delta y=Vt -1/2gt^2 assuming gravity is -9.8. As a result of this double negative you end up adding the latter half of the equation where it appears you have subracted by adding a negative. Give that a try and see if it gives you a better answer
 
  • #3
well...look at your second step: you are not calculating the hightest point...(and I'm not sure but -49.5 is not right: you are saiyng that y=-49.5?? the ball must be underground...xD)

hint: In the hightest point, the ball as no speed in y axis...^_^
 
  • #4
ooo thanks a lot!
 

Related to Projectile motion of a baseball problem

What is projectile motion?

Projectile motion is the motion of an object through the air under the influence of gravity. It follows a parabolic path, meaning it moves both vertically and horizontally at the same time.

How do you calculate the initial velocity in a baseball projectile motion problem?

The initial velocity in a baseball projectile motion problem can be calculated using the formula v0 = √(x/tanθ - (1/2)g(x/cosθ)^2), where x is the horizontal distance, θ is the launch angle, and g is the acceleration due to gravity (9.8 m/s²).

What factors affect the trajectory of a baseball in projectile motion?

The trajectory of a baseball in projectile motion is affected by factors such as the initial velocity, launch angle, air resistance, and the force of gravity. These factors can change the path of the ball and determine its final landing point.

How do you calculate the maximum height of a baseball in projectile motion?

The maximum height of a baseball in projectile motion can be calculated using the formula h = (v0sinθ)^2 / 2g, where h is the maximum height, v0 is the initial velocity, and θ is the launch angle.

What is the range of a baseball in projectile motion?

The range of a baseball in projectile motion is the horizontal distance it travels before reaching the ground. It can be calculated using the formula R = (v0^2 sin2θ) / g, where R is the range, v0 is the initial velocity, and θ is the launch angle.

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