Projectile motion of a rolling ball

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A ball rolls off a stairway with a horizontal velocity of 1.50 m/s, and the steps are 20 cm high and wide. To determine which step the ball will hit first, the relationship between horizontal displacement and height must be analyzed. The equations of motion indicate that the ball will impact at the point where the height and horizontal distance are equal. By solving for time and using the expressions for horizontal and vertical motion, the specific step can be identified. This problem emphasizes the application of projectile motion principles in a real-world scenario.
lolimcool
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Homework Statement


a ball rolls off the top of a stairway with a horizontal velocity of magnitude 1.50m/s. The steps are 20cm high and 20 cm wide. Which step will the ball hit first?

Homework Equations


d = v1t + at^2
a = -9.8m/s^2
t= 2viSinθ/ 9.8
horizontal displacement = vi^2Sin2θ/ 9.8

The Attempt at a Solution


i actually have no idea what I am doing
 
Last edited:
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Hi lolimcool, welcome to PF.
The step has equal height and width.
So the ball will hit the place where h and x are the same.
Write down the expression for x and h. Solve for t. Then find step where he ball hits.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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