Projectile Motion Question To Find Unknown Variable (Initial Velocity)

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The discussion revolves around solving a projectile motion problem to determine the initial velocity needed for a projectile to reach a mountain climber stranded 30 m above the ground, with a horizontal distance of 50 m and an angle of 55°. The user attempts to find the time of flight (Δt) using the horizontal distance and the horizontal component of the initial velocity. After calculating Δt, they substitute it into the vertical motion equation to solve for the initial velocity (V0). The user arrives at an initial velocity of 30.06 m/s and seeks confirmation on the correctness of their approach and equations used. The overall method and calculations appear to be on the right track.
salmayoussef
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Hey all! I've tried solving this problem every way I could think of and I wanted to see if I'm doing this even remotely right. Mind helping me out?

Homework Statement


Problem: A mountain climber is stranded on a ledge 30 m above the ground. Rescuers on the ground want to shoot a projectile to him with a rope attached it. If the projectile is directed upward at an initial angle of 55° from a horiontal distance of 50 m, derermine the intial speed the projectile must have in order to land on the ledge.

Given:
dx = 50 m
dy = 30 m
θ = 55°
g = -9.8 m/s2

Required:
Δt
V0

Homework Equations


Not sure if I used the proper equation but: d = V * t - (1/2)(-9.8)(t)2

The Attempt at a Solution


I tried finding Δt first by using t = dx/Vx = 50/(cos55 * V0)

After finding the time, I used it an inputed it into the equation and canceled out the V0 in the numerator and denominator then I was left with one V which I had to find by rearranging the equation.

30 m = (sin55 * V0)(50/(cos55 * V0) - 4.9(50/cos55 * V0)2

After rearranging it, I ended up with 30.06 m/s as the initial velocity. Am I using the right equation?
 
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I haven't checked your working but the approach looks correct.
 

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