Hi guys, I am stuck with a problem here. First, It is given that for 2-dimensional projectile motion, a trajectory of 45 degrees will yield the greatest range. However, how do I show that angles that differ from 45 degrees by the same amount will yield the same range? For example, the range of a 40 degree angle will equal that of a 50 degree angle? I know that the range of a projectile as a function of time is given by V^2 * sin(2ø) / g where V is the initial velocity and ø is the angle. I just don't know how to prove that the angle 45 + c will give give the same range as 45 - c, can anyone help me please?